Download Algebras, Rings and Modules: Lie Algebras and Hopf Algebras by Michiel Hazewinkel PDF

By Michiel Hazewinkel

The most aim of this publication is to offer an creation to and purposes of the speculation of Hopf algebras. The authors additionally speak about a few very important points of the idea of Lie algebras. the 1st bankruptcy may be seen as a primer on Lie algebras, with the most aim to give an explanation for and end up the Gabriel-Bernstein-Gelfand-Ponomarev theorem at the correspondence among the representations of Lie algebras and quivers; this fabric has no longer formerly seemed in publication shape. the subsequent chapters also are "primers" on coalgebras and Hopf algebras, respectively; they target particularly to offer enough historical past on those themes to be used frequently a part of the booklet. Chapters 4-7 are dedicated to 4 of the main attractive Hopf algebras presently recognized: the Hopf algebra of symmetric services, the Hopf algebra of representations of the symmetric teams (although those are isomorphic, they're very diversified within the facets they bring about to the forefront), the Hopf algebras of the nonsymmetric and quasisymmetric services (these are twin and either generalize the former two), and the Hopf algebra of diversifications. The final bankruptcy is a survey of purposes of Hopf algebras in lots of diversified components of arithmetic and physics. designated positive factors of the booklet comprise a brand new method to introduce Hopf algebras and coalgebras, an in depth dialogue of the numerous common houses of the functor of the Witt vectors, a radical dialogue of duality features of the entire Hopf algebras pointed out, emphasis at the combinatorial features of Hopf algebras, and a survey of purposes already pointed out. The publication additionally comprises an intensive (more than seven hundred entries) bibliography.

Show description

Read Online or Download Algebras, Rings and Modules: Lie Algebras and Hopf Algebras PDF

Similar algebraic geometry books

Singularities, Representation of Algebras and Vector Bundles

It's renowned that there are shut family among sessions of singularities and illustration conception through the McKay correspondence and among illustration conception and vector bundles on projective areas through the Bernstein-Gelfand-Gelfand development. those family members in spite of the fact that can't be thought of to be both thoroughly understood or absolutely exploited.

Understanding Geometric Algebra for Electromagnetic Theory

This publication goals to disseminate geometric algebra as an easy mathematical device set for operating with and figuring out classical electromagnetic conception. it truly is objective readership is a person who has a few wisdom of electromagnetic conception, predominantly usual scientists and engineers who use it during their paintings, or postgraduate scholars and senior undergraduates who're looking to develop their wisdom and elevate their figuring out of the topic.

Additional resources for Algebras, Rings and Modules: Lie Algebras and Hopf Algebras

Example text

Let 0 → F → F → F be an exact sequence of sheaves on X. Show that the sequence of Abelian groups 0 → F (X) → F(X) → F (X) is exact. 40 2. 5. (Supports of sheaves) Let F be a sheaf on X. Let Supp F = {x ∈ X | Fx = 0}. We want to show that in general, Supp F is not a closed subset of X.

2. Let F be a sheaf on X. Let s, t ∈ F(X). Show that the set of x ∈ X such that sx = tx is open in X. 3. (Sheaf associated to a presheaf ) Let us fix a topological space X. Let F be a presheaf on X. 7. (a) Let U = {Ui }i be an open covering of X. Let FU (X) = Ker d1 . For any open subset W of X, we define in the same way a group FU (W ) relative to the covering {W ∩ Ui }i of W . Show that FU is a presheaf on X and that we have a morphism of presheaves F → FU . (b) Let V = {Vk }k be another open covering of X.

A−1 (1 + δ + δ 2 + . . ) ˆ Hence this is a local ring. We already know that it is is the inverse of α in A. 20. (c) Let n ≥ 1. We have nn = mn B. Since the composition A/mn → B/mn B → ˆ n Aˆ is surjective. It remains to show ˆ A/mn Aˆ is an isomorphism, B/mn B → A/m n ˆ that it is injective; that is, that m A ∩ B = mn B. We have B = A + mB = A + m2 B = · · · = A + mn B, so every element b ∈ B can be written b = a + ε ˆ If, moreover, b ∈ mn A, ˆ then a ∈ mn Aˆ ∩ A = mn , with a ∈ A, ε ∈ mn B ⊆ mn A.

Download PDF sample

Rated 4.84 of 5 – based on 22 votes