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Rst-of, and second-of. No, so our proof should be shorter, right? Now that we have met J-Bob, we can’t wait. Should we read this chapter one more time? Perhaps we shall, over a bowl of oatmeal, dates, and blueberries. Chapter 3 What value is (list0? 'oatmeal) equal to? What value is (list0? '()) equal to? 1 2 'nil, because 'oatmeal is not a list. 't, because '() is the empty list. What value is (list0? '(toast)) equal to? Deﬁne list0?. Very funny. Try again. Is list0? total? “list0? , the expression (list0?
Still looing at frame 36, what are the questions of the ifs that have the conclusion in their else? Looking at frame 33, is the focus found in the else of any ifs with the questions (brillig '(callooh callay)) and (uﬃsh '(callooh callay))? Then, we can not use jabberwocky to rewrite the focus in frame 33. The conclusion from frame 36 does not meet the second part of the third condition. Let’s try again. Can we use jabberwocky to rewrite this focus instead? 37 38 39 40 41 42 43 No, it is not, thus meeting our second condition.
T 35 Is second-of-pair a theorem? In ﬁrst-of-pair, we used the Law of Defun on pair ﬁrst, but in second-of-pair, we used the Law of Defun on pair second. No, not in this particular case. Certainly, depending on the proof. If we can ﬁnd a proof one way, we can always ﬁnd it another. If the second way goes wrong, we can “back up” to where we started and do it the ﬁrst way again. But some approaches will ﬁnd a proof faster than others. What does in-pair? do? 22 23 24 25 26 27 (defun in-pair? ))) We can try to prove this claim.